Jon Jagger
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Another thread on resistance vs sensitivity has got me thinking...
Suppose I'm feeder fishing with a quivertip, there's no tow, I have a straight line (braid so we can ignore stretch) from tip, and the tip is about 90 degrees to the line. If a fish takes the bait and moves away from the rod 1cm then this will cause 1cm of movement on the tip.
Now imagine the same setup but with the rod pointing directly at the feeder (zero angle at the tip) and a sidewinder style indicator attached between the bottom two butt rings. Again a fish takes the bait and moves away from the rod 1cm. How many cm movement will this cause at the sidewinder? The answer is it depends. A sidewinder holds the line _away_ from the rod and the shape of the triangle formed determines the number of cm's movement. Viz it depends on
1) how far apart the two rings are
2) how near the middle of the two rings the sidewinder eye is
3) how far from the rod the sidewinder eye already is.
You can use pythogoras's theorem to work it out: if 1) is 80cm and 2) is exactly in the middle and 3) is 20cm then 1cm pull by the fish creates just over 2cm of sidewinder movement. And if 3) is 6cm then 1cm of pull by the fish gives an amazing 6cm of movement at the sidewinder! If you move the sidewinder eye further and further from the rod you get to a point where 1cm of pull by the fish will equate to 1cm of sidewinder movement. If you then move the sidewinder eye further away still (assuming it's long enough) you get _less_ than 1cm sidewinder movement for 1cm fish pull. Sensitivity on a sidewinder is variable!
Clearly the closer the sidewinder eye is to the rod the greater the sensitivity but the greater the resistance (since the sidewinder is bent more and is pulling back more). What I'm struggling to figure out is how the resistance for the sidewinder compares to the resistance for the quivertip. In short, does the different way the sidewinder works mean it can be more sensitive than a quivertip for the same resistance?
Suppose I'm feeder fishing with a quivertip, there's no tow, I have a straight line (braid so we can ignore stretch) from tip, and the tip is about 90 degrees to the line. If a fish takes the bait and moves away from the rod 1cm then this will cause 1cm of movement on the tip.
Now imagine the same setup but with the rod pointing directly at the feeder (zero angle at the tip) and a sidewinder style indicator attached between the bottom two butt rings. Again a fish takes the bait and moves away from the rod 1cm. How many cm movement will this cause at the sidewinder? The answer is it depends. A sidewinder holds the line _away_ from the rod and the shape of the triangle formed determines the number of cm's movement. Viz it depends on
1) how far apart the two rings are
2) how near the middle of the two rings the sidewinder eye is
3) how far from the rod the sidewinder eye already is.
You can use pythogoras's theorem to work it out: if 1) is 80cm and 2) is exactly in the middle and 3) is 20cm then 1cm pull by the fish creates just over 2cm of sidewinder movement. And if 3) is 6cm then 1cm of pull by the fish gives an amazing 6cm of movement at the sidewinder! If you move the sidewinder eye further and further from the rod you get to a point where 1cm of pull by the fish will equate to 1cm of sidewinder movement. If you then move the sidewinder eye further away still (assuming it's long enough) you get _less_ than 1cm sidewinder movement for 1cm fish pull. Sensitivity on a sidewinder is variable!
Clearly the closer the sidewinder eye is to the rod the greater the sensitivity but the greater the resistance (since the sidewinder is bent more and is pulling back more). What I'm struggling to figure out is how the resistance for the sidewinder compares to the resistance for the quivertip. In short, does the different way the sidewinder works mean it can be more sensitive than a quivertip for the same resistance?